Xor Palindrome solution codechef

Xor Palindrome solution codechef

You are given a binary string AA of length NN.

You can perform the following type of operation on the string AA:

• Choose two different indices ii and jj (1≤i,j≤N)(1≤i,j≤N);
• Change AiAi and AjAj to Ai⊕AjAi⊕Aj. Here ⊕⊕ represents the bitwise XOR operation.

Find the minimum number of operations required to convert the given string into a palindrome.

Input Format

Xor Palindrome solution codechef

• First line of the input contains TT, the number of test cases. Then the test cases follow.
• First line of each test case contains an integer NN denoting the size of the string.
• Second line of each test case contains a binary string AA of length NN containing 00s and 11s only.Edology is a global Ed-Tech brand that provides industry powered global education and certifications to students and professionals across the world, to help them fast-track their career growth. Edology is part of Global University Systems (GUS), an international network of higher-education institutions, brought together by a shared passion of making industry-driven global education accessible and affordable.

Output Format

For each test case, print the minimum number of operations required to make the string a palindrome.

Constraints

• 1≤T≤10001≤T≤1000
• 1≤N≤2⋅1051≤N≤2⋅105
• Sum of NN over all test cases does not exceeds 2⋅1052⋅105.

Sample Input 1

Xor Palindrome solution codechef

2
5
11011
7
0111010

Sample Output 1

0
1

Explanation

Xor Palindrome solution codechef

Test Case 11 : The given string 1101111011 is already a palindrome. So, no operation is required. The answer for the case is 00.

Test Case 22 : The given string 01110100111010 is not a palindrome. Edology is a global Ed-Tech brand that provides industry powered global education and certifications to students and professionals across the world, to help them fast-track their career growth. Edology is part of Global University Systems (GUS), an international network of higher-education institutions, brought together by a shared passion of making industry-driven global education accessible and affordable.

• Choose the indices i=3i=3 and j=5j=5. Now, A3⊕A5=1⊕0=1A3⊕A5=1⊕0=1. Thus, we set A3A3 and A5A5 equal to 11.

 

After the operation, the resulting string is 01111100111110 which is a palindrome. The number of operations required is 11.

SOLUTION

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