[Coding] Spiral Matrix IV solution leetcode
You are given two integers `m`

and `n`

, which represent the dimensions of a matrix.
You are also given the `head`

of a linked list of integers.
Generate an `m x n`

matrix that contains the integers in the linked list presented in **spiral** order **(clockwise)**, starting from the **top-left** of the matrix. If there are remaining empty spaces, fill them with `-1`

.
Return *the generated matrix*.

## [Coding] Spiral Matrix IV solution leetcode

**Example 1:**

Input:m = 3, n = 5, head = [3,0,2,6,8,1,7,9,4,2,5,5,0]Output:[[3,0,2,6,8],[5,0,-1,-1,1],[5,2,4,9,7]]Explanation:The diagram above shows how the values are printed in the matrix. Note that the remaining spaces in the matrix are filled with -1.

**Example 2:**

Input:m = 1, n = 4, head = [0,1,2]Output:[[0,1,2,-1]]Explanation:The diagram above shows how the values are printed from left to right in the matrix. The last space in the matrix is set to -1.

**Constraints:**

## Spiral Matrix IV solution leetcode

`1 <= m, n <= 10`

^{5}`1 <= m * n <= 10`

^{5}- The number of nodes in the list is in the range
`[1, m * n]`

. `0 <= Node.val <= 1000`